Ludhan Wijaya / 2TA01 / 13315872
a. Persoalan :
Cj
|
80
|
100
|
0
|
0
|
0
|
||
Basis
|
X1
|
X2
|
S1
|
S2
|
S3
|
bj
|
|
3
|
2
|
1
|
0
|
0
|
18
|
||
2
|
4
|
0
|
1
|
0
|
20
|
||
0
|
1
|
0
|
0
|
0
|
4
|
||
Zj
|
|||||||
(Cj - Zj)
|
|||||||
b. Penyelesaian :
Cj
|
80
|
100
|
0
|
0
|
0
|
Ratio
|
|||
Basis
|
X1
|
X2
|
S1
|
S2
|
S3
|
bj
|
18 : 2 = 9
|
||
S1
|
0
|
3
|
2
|
1
|
0
|
0
|
18
|
20 : 4 = 5
|
|
S2
|
0
|
2
|
4
|
0
|
1
|
0
|
20
|
4 : 1 = 4
|
|
S3
|
0
|
0
|
1
|
0
|
0
|
4
|
BK
|
(Pivot)
|
|
Zj
|
0
|
0
|
0
|
0
|
0
|
||||
(Cj - Zj)
|
80
|
100
|
0
|
0
|
0
|
||||
KK
|
|||||||||
Cj
|
80
|
100
|
0
|
0
|
0
|
Ratio
|
|||
Basis
|
X1
|
X2
|
S1
|
S2
|
S3
|
bj
|
10 : 3 = 3,3
|
||
S1
|
0
|
3
|
0
|
1
|
0
|
0
|
10
|
BK
|
12 : 2 = 6
|
S2
|
0
|
2
|
2
|
0
|
0
|
0
|
12
|
4 : 0 = ꝏ
|
|
X2
|
100
|
0
|
1
|
0
|
0
|
0
|
4
|
(Pivot)
|
|
Zj
|
0
|
100
|
0
|
0
|
0
|
400
|
|||
(Cj - Zj)
|
80
|
0
|
0
|
0
|
0
|
||||
KK
|
|||||||||
Cj
|
80
|
100
|
0
|
0
|
0
|
||
Basis
|
X1
|
X2
|
S1
|
S2
|
S3
|
bj
|
|
X1
|
80
|
1
|
0
|
0,3
|
0
|
0
|
3,3
|
S2
|
0
|
2
|
2
|
0
|
0
|
0
|
12
|
X2
|
100
|
0
|
1
|
0
|
0
|
0
|
4
|
Zj
|
80
|
100
|
26,7
|
0
|
0
|
666,67
|
|
(Cj - Zj)
|
0
|
0
|
-26,7
|
0
|
0
|
||
Karena Cj – Zj ≤ 0 , maka sudah optimum dengan keuntungan
atau laba sebesar 666,67
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